Question

Find the sum of ap -37,-33,-29____ to 10 terms

Answer 1

Answer:

sn=n/2[2a+(n-1)d]

d=4

n=10

a=-37

Put the value...

=5(-74+36)

=5×-38

=-190

Answer 2

Answer:

-190

Explaination:

Here AP is -37, -33, -29 ...............

a1= -37

a2= -33

d= a2-a1

=(-33)-(-37)

=-33+37

=4

sum upto 10 terms

then n=10

Sn = (n/2)[2a + (n-1)d]

S(10)=(10/2)[2(-37)+(10-1)4]

=5[-74 +9×4]

=5[-74+36]

= 5[ -38 ]

= -190