Question

find the sum of arithmetic progression

0.6 ,1.7, 2.8,...........up to 100 terms​

Answer 1

Answer:

Step-by-step explanation:

a=0.6,d=1.7-0.6=1.1,n=100

S100=100/2(1.2+99x1.1)

=50(120.1)

=5,505

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Answer 2

0.6, 1.7 , 2.8....

First term ( a)= 0.6

common difference (d)= 1.7 - 0.6 = 1.1

Sn= n/2 ( 2 a+ ( n-1) d)

S100 =100/2. ( 2( 0.6 ) + (100-1) × 1.1)

= 50( 1.2 + 99× 1.1)

= 50( 1.2 + 108.9)

= 50( 110.1)

= 5505

OR

0.6 , 1.7, 2.8.......

6/10 , 17/ 10 , 28 /10......

its sum is ( 6 +17+28.....)/ 10

6+17+ 28.......

a= 6

d= 17 -6 = 11

S= 100/2 ( 2(6) +( 100 -1) 11)

= 50( 12 + 99× 11)

= 50( 12 +1089)

= 50( 1101)

= 55050

S100 = 55050/10 = 5505