Math, asked by Tinisha, 1 year ago

find the sum of arithmetic progression
8,3,-2 ,.........up to 22 terms


Answers

Answered by aami21
6

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a=8

n=22

d=-5

S22=22/2{2*8+21*-5}

=11(16-105)

=-979

{\boxed{\red{-979}}}

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Answered by Anonymous
11

ANSWER :

1, 4, 7, 10 ,13 etc.....are called sequence of an A.P ( arithmetic progression ).

  • 1st term   : a = a₁ = 1
  • 2nd term : a₂ = 4 = ( 1 + 3 ) = a + d
  • Common difference ( d ) : a₂ - a₁
  • 3rd term : a₃ = a + 2d

General Formula of an A.P : an = a + ( n - 1 ) d

( an = last term )

For finding sum of the A.P we have another formula :

  • Sn = n/2 [ 2a + ( n - 1 ) d

( Sn donates : Sum of the A.P )

GIVEN A.P =  8,3,-2 ,.........up to 22

a = 8 ( first term of an Ap )

d = a₂ - a₁ = 3 - 8

= - 5  (Common Difference of the given AP )

n = 22  ( last term )

Now we have to Put these values in the formula :

  • Sn = n/2 [ 2a + ( n - 1 ) d

S₂₂ =  22 / 2 [ 2 × 8 + ( 22 - 1 ) ( ₋ 5 )

S₂₂ =  11 [ 16 + ( 21 ) ( - 5 ) ]

S₂₂ =  11 [ 16 - 105 ]

S₂₂ =  11 [ ₋ 89 ]

S₂₂ =  ₋ 979

∴ The sum of arithmetic progression  8,3,-2 ,.........up to 22 terms is

  • S₂₂ =  ₋ 979
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