Find the sum of cubes of first ten natural numbers
Answers
Answered by
1
heya friend
The sum of the cubes of first n positive integers is given by [n(n+1)/2]^2
If n = 10, the sum is 55^2.
The sum of the cubes of first n positive integers is given by [n(n+1)/2]^2
If n = 10, the sum is 55^2.
Similar questions