Question

Find the sum of different 10th place digits of all perfect square numbers whose unit's place digits are perfect square.​

Answer 1

Sum of different 10th place digits would be 24.

Step-by-step explanation:

Get the two digit perfect square number as

4² = 16

5² = 25

6² = 36

7² = 49

8² = 64

9² = 81

Out of these perfect square numbers 16, 25, 36, ........

49 is the number in which 9  is the number at unit place is a perfect square of 3.

Similarly 64 is the second number in which 4 is the number at unit place is a perfect square of 2.

and 81 is the third number in which 1 is the number at unit place is a perfect square of 1.

Now the sum of different 10th place digits = 1 + 2 + 3 + 4 + 6 + 8 = 24

Therefore, sum of different 10th place digits would be 24.

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