Question

3. Four dice are rolled. The number of ways in which at least one die shows 3, is​

Answer 1

Answer:

Step-by-step explanation: well,each die has six different configurations,one of them having a 3 on it.

So there ara 5 configurations on each die with no 3s.

Altogether that's 5^4=625 configurations with no 3s.

How many dice configurations are there altogether?

6^4=1296

So the number of configurations in which atleast one die has a 3 on it must be the number of configurations altogether,minus the number of configurations that don't have 3s.

6^4 - 5^4 = 671.