find the sum of even integers from 1 to 1001
Answers
Answered by
0
I'll answer if the points give me 100
Step-by-step explanation:
Answered by
3
Answer:
The series is given as,
102,104,..........,998
a=102
d=104−102=2
a
n
=a+(n−1)d
998=102+(n−1)2
896=2(n−1)
448=n−1
n=449
S
n
=
2
n
[2a+(n−1)d]
S
449
=
2
449
[2(102)+(449−1)2]
=
2
449
×1100
=246,950
Step-by-step explanation:
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