find the sum of exteroir angle obtained on producing order the sides of polygon with 10sides
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HERE IS YOURS SOLUTION;
◆ We know that, exterior angle + interior adjacent angle = 180°.
So, if the polygon has 10 sides, then
◆ Sum of all exterior angles + Sum of all interior angles = 10 × 180°
So, sum of all exterior angles = 10× 180° - Sum of all interior angles
◆ Sum of all exterior angles = 10 × 180° - (10 -2) × 180°
= 10 × 180° - 10 × 180° + 2 × 180°
= 360°
◆ Therefore, we conclude that sum of all exterior angles of the polygon having 10 sides = 360° ◆
HOPE IT HELPS
◆ We know that, exterior angle + interior adjacent angle = 180°.
So, if the polygon has 10 sides, then
◆ Sum of all exterior angles + Sum of all interior angles = 10 × 180°
So, sum of all exterior angles = 10× 180° - Sum of all interior angles
◆ Sum of all exterior angles = 10 × 180° - (10 -2) × 180°
= 10 × 180° - 10 × 180° + 2 × 180°
= 360°
◆ Therefore, we conclude that sum of all exterior angles of the polygon having 10 sides = 360° ◆
HOPE IT HELPS
DonDj:
Is my answer correct
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