find the sum of first
10 B even natural nomber
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Answered by
1
Answer:
the sum of the first 10 even natural numbers is 110.
Explanation:
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110
To Find:
The sum of the first 10 even natural numbers that are there.
The formula that is used for calculating the sum of n term of an AP:
Sn = n/2(2a + (n - 1) d
The first term of the AP = 2
The value of n = 10
The common difference of the AP(d) = 2
Substituting all the values which are known to us into this formula we get:
Sn = 10/2 (2 x 2) + (10 - 1) x 2
Sn = 5 (4 + 9 x 2)
Sn = 5 x (4 + 18)
Sn = 5 x (22)
Sn = 110
Therefore, the sum of the first 10 even natural numbers is 110.
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