find the sum of first 10 multiple of 6
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the first multiple of 6 are 6, 12, 18, 24 ,30 ,36
n= 10
a =t1 = 6
tn = 361
now
Sn = n/2 [ t1 + tn ]
=10/2 [ 6+36]
=5 [42]
=210
the sum of 1st 10 no. multiple of 6 are 210
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First 10 multiple of 6
U have given then answer for first 6 multiple of 6
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