Question

find the sum of first 10 multiples of 2

Answer 1

Step-by-step explanation:

a = 2

d = 2

S10 = n/2[2a +(n-1)d]

= 10/2 [4 + 18]

= 10/2 [22]

= 10 × 11

= 110

Hope it helps uh!!

Answer 2

Concept:

Sequence and Series: Arithmetic progression (AP)

Arithmetic progression : It is a sequence of numbers in which every number differs the previous number by a constant value which is called common difference of the sequence.

And, any sequence of multiples of a particular number is always an arithmetic progression with the common difference equals the number itself.

Find:

The sum of first 10 multiples of 2.

Solution:

The AP of multiples of 2 is 2, 4, 6, ---------- and so on.

From the above AP, we have

First term, a = 2

Common difference, d = a₂ - a₁ = 4 - 2 = 2

Sum of n terms of AP is given by,

Sₙ = n/2[2a (n-1)d]

Here n = 10

∴ S₁₀ = 10/2 [2(2) + (10 -1)(2)]

         = 5 [ 4 + (9)(2)]

         = 5 [ 4 + 18 ]

         = 5 × 22

         = 110

Hence, the sum of first 10 multiples of 2 is 110.

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