Question

find the sum of first 10 multiples of 6​

Answer 1

6+12+18+24+30+36+42+48+54+60=330

Answer 2

Answer:

330

Step-by-step explanation:

sn=n/2 (2a+(n-1)d)

ap formed will be: 6,12,18...........

given,

a=6

d=6

n=10

sn=10/2 (2×6+(10-1)6)

sn=5 (12+54)

sn=5×66

sn=330