Question

find the sum of first 10 multiples of 8​

Answer 1

FIRST 10 MULTIPLES OF 8 ARE:

8,16,24,32,40,48,56,64,72,80

SUM OF FIRST TEN MULTIPLES=

8+16+24+32+40+48+56+64+72+

80=440

440 IS THE CORRECT ANSWER

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Answer 2

Step-by-step explanation:

MULTIPLES OF 8 ARE

8,16,24,32.......

TO FIND:SUM OF FIRST 10 MULTIPLES OF 8

FIRST TERM(A1)=8

COMMON DIFFERNCE (D) = 8

LAST TERM(l)= 80

$s n = \frac{n}{2} (a + l)$

PUTTING THE VALUES U GET

$\frac{10}{2} (8 + 80)$

ON SOLVING IT BECOMES

440

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