Question

find the sum of first 10 terms of an ap 8 4 0 - 4 - 8

Answer 1

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Answer 2

The sum of an A P = n/2(2a + (n-1)d)
a = 8
n = 10
d = -4
Then Sn = 10/2(2x8 + (10-1)*-4)
Sn = 5(16 - 36)
=5(-20)
=-100