find the sum of first 10 terms of the A.P . 4+6+8........
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Answered by
4
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n =10. ,a=4. ,d=6-4=2
an. = a+(n-1)d
= 4+(10-1)2
=4+(9)2
=4+18
=22
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________________________________________________________________________
___________________________________
n =10. ,a=4. ,d=6-4=2
an. = a+(n-1)d
= 4+(10-1)2
=4+(9)2
=4+18
=22
PLEASE MARK ME AS A BRAINLIST..
say thanks to me..or follow me
good bye...☺️☺️☺️
________________________________________________________________________
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Answered by
1
n=10. a= 4. d. = 6-4= 2
an= a+(n-1)d
= 4+(10-1)2
= 4+(9)2
=4+18
= 22
an= a+(n-1)d
= 4+(10-1)2
= 4+(9)2
=4+18
= 22
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