Question

find the sum of first 10 terms of the apx-8 x-2 x+4........?

Answer 1

given ,
n=10
a=x-8
d=x-2-(x-8)
=x-2-x+8
=6
Sum= n/2[2a+(n-1)d]
= 10/2[2(x-8)+(10-1)6]
= 5[2x-16+9×6]
= 5[2x-16+36]
= 5[2x+20]
= 10x+100