find the sum of first 100 natural numbers
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Answered by
7
step 1 address the formula, input parameters & values.
Input parameters & values:
The number series 1, 2, 3, 4, . . . . , 99, 100.
The first term a = 1
The common difference d = 1
Total number of terms n = 100
step 2 apply the input parameter values in the formula
Sum = n/2 x (a + Tn)
= 100/2 x (1 + 100)
= 10100/2
1 + 2 + 3 + 4 + . . . . + 99 + 100 = 5050
Therefore, 5050 is the sum of positive integers upto 100.
Input parameters & values:
The number series 1, 2, 3, 4, . . . . , 99, 100.
The first term a = 1
The common difference d = 1
Total number of terms n = 100
step 2 apply the input parameter values in the formula
Sum = n/2 x (a + Tn)
= 100/2 x (1 + 100)
= 10100/2
1 + 2 + 3 + 4 + . . . . + 99 + 100 = 5050
Therefore, 5050 is the sum of positive integers upto 100.
Answered by
0
Use the formula-
n(n+1)/2… answer 'll be 5050.
n(n+1)/2… answer 'll be 5050.
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