Find the sum of first 1000 positive integer
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Answered by
26
Hi !
The positive integers form an ap :-
1,2,3,4 ....... 1000
a = 1
d = 1
l = 1000
l = a + (n-1)d
1000 = 1 + n - 1
n = 1000
sum = n/2[a + l]
= 1000/2 [ 1 + 1000]
= 500 x 1001
= 500500
sum of first 1000 positive integer = 500500
The positive integers form an ap :-
1,2,3,4 ....... 1000
a = 1
d = 1
l = 1000
l = a + (n-1)d
1000 = 1 + n - 1
n = 1000
sum = n/2[a + l]
= 1000/2 [ 1 + 1000]
= 500 x 1001
= 500500
sum of first 1000 positive integer = 500500
Answered by
6
Positive integers = Natural numbers.
We know that Sum of first n natural numbers is n ( n+1)/2
Sum of first 1000 positive integers or natural numbers =1000*1000+1/2
=500*1001
=500500
therefore sum of first 1000 positive integer is 5,00,500
We know that Sum of first n natural numbers is n ( n+1)/2
Sum of first 1000 positive integers or natural numbers =1000*1000+1/2
=500*1001
=500500
therefore sum of first 1000 positive integer is 5,00,500
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