find the sum of first 10th term of the AP 0.6,1.7,2.8,.....
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Answer:
Step-by-step explanation:
Given AP: 0.6, 1.7, 2.8, ............
a = 0.6
d = 1.7 - 0.6 = 1.1
n = 10
Sn = n/2[ 2a + (n-1)d]
= 10/2 [ 2(0.6) + (10 - 1)×(1.1)]
= 5[ 1.2 + (9 × 1.1)]
= 50[ 1.2 + 9.9]
=5[11.1]
= 55.5
Hope it helped
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