Find the sum of first 11 terms of an
A.P is 2, 5, 8,………………
Answers
Answer :
S(11) = 187
Note :
★ A.P. (Arithmetic Progression) : A sequence in which the difference between the consecutive terms are equal is said to be in A.P.
★ If a1 , a2 , a3 , . . . , an are in AP , then
a2 - a1 = a3 - a2 = a4 - a3 = . . .
★ The common difference of an AP is given by ; d = a(n) - a(n-1) .
★ The nth term of an AP is given by ;
a(n) = a1 + (n - 1)d .
★ The sum of nth terms of an AP is given by ; S(n) = (n/2)×[ 2a + (n - 1)d ] .
or S(n) = (n/2)×(a + l) , where a is the first term , l is the last term and d is the common difference .
Solution :
• Given AP : 2 , 5 , 8 , . . .
• To find : Sum of first 11 terms , S(11) = ?
We have ,
AP : 2 , 5 , 8 , . . .
Clearly ,
• First term , a = 2
• Common difference , d = a2-a1 = 5-2 = 3
Now ,
We know that , the sum of first n terms of an AP is given as ;
S(n) = (n/2)×[ 2a + (n - 1)d ]
Thus ,
The sum of first 11 terms of the AP will be ;
=> S(11) = (11/2)×[ 2a + (11 - 1)d ]
=> S(11) = (11/2)×[ 2a + 10d ]
=> S(11) = (11/2)×2×(a + 5d)
=> S(11) = 11×(a + 5d)
=> S(11) = 11×(2 + 5•3)
=> S(11) = 11×(2 + 15)
=> S(11) = 11×17
=> S(11) = 187
Hence , S(11) = 187 .
Añswèr :
187
Solution :
- Given A.P = 2,5,8,......
- First term , a = 2
- Common difference , d = t2-t1 =>5-2=3
- Sum of 11 terms = ?
- Sum of n terms = n/2 (a+a(n))
- a(n) = a+(n-1)d
- a(11) = 2+(11-1)3
- a(11) = 2+30
- a(11) = 32
- Sum of 11 terms , S(11) = 11/2 (2+32)
- S(11) = 11/2 (34)
- S(11) = 11×17
- S(11) = 187
Therefore sum of 11 terms of given A.P is 187
Note :
- Arithmetic progression : A sequence which has a constant common difference is called as arithmetic progression.
- Common difference : The difference between two successive terms of an A.P is called as common difference.
Important formulàé :
- a(n) = a +(n-1)d , a = first term , d = common difference , a(n) = nth term
- S(n) = n/2 (a+a(n))
(or)
- S(n) = n/2(2a+(n-1)d)
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Students generally get confused between the Quéstìons like , finding the sum of n terms and finding the nth term , kindly don't get confused .
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