Find the sum of first 15 terms of AP 5,8,11,14.....
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given a=5
d=3
sum of first 15 term =n/2[2a+(n-1)×d]
=15/2[2×5+(14)×3]
=15/2×52
=15×26
=390
d=3
sum of first 15 term =n/2[2a+(n-1)×d]
=15/2[2×5+(14)×3]
=15/2×52
=15×26
=390
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