Find the sum of first 16 terms of an A.P. whose first term is 4 and common difference is - 3.
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1
Answer:
-296
Step-by-step explanation:
a=4
d= -3
sn= n/2[2a + (n-1)d]
= 16/2[2X4 + (16-1)(-3)]
= 8[8 + (-45)]
=8[-37]
= -296
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