Question

Find the sum of first 16 terms of an A.P. whose first term is 4 and common difference is - 3.

Answer 1

Answer:

-296

Step-by-step explanation:

a=4

d= -3

sn= n/2[2a + (n-1)d]

   = 16/2[2X4 + (16-1)(-3)]

   = 8[8 + (-45)]

    =8[-37]

    = -296