1-sin A
(ii)
sec A-tan A
1 + sin A
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Answer:
√{(1 - sina)/(1 + sina)} = seca - tana
Step-by-step explanation:
L.H.S. = √{(1 - sina)/(1 + sina)}
= √[{(1 - sina)(1 - sina)}/{(1 + sina)(1 - sina)}]
= √{(1 - sina)²/(1 - sin²a)}
= √{(1 - sina)²/cos²a}
= √{(1 - sina)/cosa}²
= (1 - sina)/cosa
= 1/cosa - sina/cosa
= seca - tana = R.H.S.
Hence proved.
Trigonometry: Trigonometry is the study of angles and relations between angles and their sin, cos, tan, cosec, sec, cot ratios. There are many formulae for calculations:
• sin²A + cos²A = 1
• sec²A - tan²A = 1
• cosec²A - cot²A = 1
• sin2A = 2 sinA cosA
• cos2A = cos²A - sin²A
• tan2A = 2 tanA / (1 - tan²A)
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