Find the sum of first 16 terms of the ap 10 6 2,...
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a=10
d=6-10
d=-4
n=16
Sn=n/2(2a+(n-1)d)
16/2(2*10+(15)(-4))
8(20-60)
8(-40)
-320 Ans
d=6-10
d=-4
n=16
Sn=n/2(2a+(n-1)d)
16/2(2*10+(15)(-4))
8(20-60)
8(-40)
-320 Ans
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