FIND THE SUM OF FIRST 20 MULTIPLE OF 9
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Answered by
2
Here,
let form an AP,
where a=9, d=9 and n=20
So,
AP:- 9,18,27,36,45......
Now,
Sum of values up to 20 terms = n/2 [a×2 + (n-1)d]
=> (20/2) [9×2 + (20-1)9]
=> (10)×(18 + 171)
=> (10)×(189)
=> 1890
So, the sum of first of 20 multiples of 9 is 1890.
Answered by
0
let form an AP
where a=9, d=9 and n=20
So,
AP:- 9,18,27,36,45...
Now,
Sum of values up to 20 terms = n/2 [a×2 + (n-1)d]
=> (20/2) [9×2 + (20-1)9]
=> (10)×(18 + 171)
=> (10)×(189)
=> 1890
So, the sum of first of 20 multiples of 9 is 1890.
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