in a figure angle BAD =70 and angle ADC =80 . calculate angle BDC,Angle BCD And angle BCA
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Answer⬇️
ABCD is a cyclic quadrilateral.We know, that
of opposite angles of a cyclic quadrilateral is 180.
Therefore,
∠BAD+∠BCD=180
=>∠BCD=180−70
=110 (ii)
∠ADC+∠ABC=180
=>72+∠ABD+∠DBC=180
=>72+56+∠CBD=180
=>∠CBD=180−128
=52
In △BCD,
∠BCD+∠DBC+∠BDC=180
=>110+52+∠BDC=180
=>∠BDC=18 (i)
hop this will help you...
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