find the sum of first 20 natural numbers.
Answers
Answered by
22
a = 1
d = 1
n= 20
Sn = n/2[ 2a +(n-1)d]
S20 = 20/2 [ 2*1 + 19*1]
S20 = 20/2 [ 2 + 19]
S20 = 10 * 21
S20 = 210
Required sum = 210
d = 1
n= 20
Sn = n/2[ 2a +(n-1)d]
S20 = 20/2 [ 2*1 + 19*1]
S20 = 20/2 [ 2 + 19]
S20 = 10 * 21
S20 = 210
Required sum = 210
gaurav2013c:
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Answered by
4
natural no.s are
1,2,3,........20
d = a2-a1
= 2-1
= 1
a = 1
n = 20
Sn = n/2(2a+(n-1)d)
S20 = 20/2 (2*1 + (20-1)1)
S20 = 10 (2+19)
= 10 (21)
= 210
1,2,3,........20
d = a2-a1
= 2-1
= 1
a = 1
n = 20
Sn = n/2(2a+(n-1)d)
S20 = 20/2 (2*1 + (20-1)1)
S20 = 10 (2+19)
= 10 (21)
= 210
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