find the sum of first 20 terms of an AP.whose first term is 3 andthe last term is 57.
Answers
Answered by
4
Hi Friend !!!
Here is ur answer !!!
Sn = n/2 (a+an)
S20 = 20/2 (3+57)
S20 = 10(60)
S20 = 600
Hope it helps u : )
Here is ur answer !!!
Sn = n/2 (a+an)
S20 = 20/2 (3+57)
S20 = 10(60)
S20 = 600
Hope it helps u : )
Answered by
2
Heya !!!
First term ( A) = 3
And,
Last term ( L) = 57
Therefore,
Sn = N/2 × ( A + L)
S20 = 20/2 × ( 3 + 57)
=> 10 × ( 60)
=> 600
HOPE IT WILL HELP YOU....... :-)
First term ( A) = 3
And,
Last term ( L) = 57
Therefore,
Sn = N/2 × ( A + L)
S20 = 20/2 × ( 3 + 57)
=> 10 × ( 60)
=> 600
HOPE IT WILL HELP YOU....... :-)
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