Find the sum of first 20 terms of the following AP :
1,4, 7, 10,
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Step-by-step explanation:
sn = n/2 {2a + ( n-1 )d}
= 20 / 2 { 2 ×1 + ( 20 - 1 ) 3}
= 10 {2+ 57 }
= 10 × 59
= 590
Sn = 590
Answered by
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a= t1 = 1 and d = 3
Sn = n/2 ( 2a +( n-1) d)
= 20 /2 ( 2(1)+ (20-1) 3)
= 10(2+(19) 3)
= 10(2+57)
= 10×59
Sn = 590
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