find the sum of first 20 terms of the series 48+56+64...
Answers
Answered by
16
Answer:
S₂₀ = 2,480
Step-by-step explanation:
Have to find the sum of first 20 terms of the series 48,56,64
First term = t₁ = 48
Difference = d = 8
20'th term = t₂₀ = a+19d
t₂₀ = 48+(19×8)
t₂₀ = 48+152 = 200
Sum of first 20 terms = ⁿ/₂(t₁+t₂₀)
n= 20
t₁=48
t₂₀=200
S₂₀ = ²⁰/₂(48+200)
S₂₀ = ²⁰/₂(248)
S₂₀ = 2,480
Answered by
1
The given series is: 48+56+64...
To find :
Solotion:
We know that,
Here, n = 20
a = 48
d = 56-48
=8
So,
Therefore, sum of 20th terms of the given series is 2500.
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