Question

Find the sum of first 201 natural numbers

Answer 1

Answer:

step 1 address the formula, input parameters & values.

Input parameters & values:

The number series 1, 2, 3, 4, . . . . , 200, 201.

The first term a = 1

The common difference d = 1

Total number of terms n = 201

step 2 apply the input parameter values in the formula

Sum = n/2 x (a + Tn)

= 201/2 x (1 + 201)

= 40602/2

1 + 2 + 3 + 4 + . . . . + 200 + 201 = 20301

Therefore, 20301 is the sum of positive integers upto 201.

Answer 2

$\huge\underline\mathfrak\green{Solution}$