find the sum of first 22 terms of an arithmetic progression 4,9,14,19
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Step-by-step explanation:
here,
a= 4
d= 5
n= 22th
Sn= n/2(2a+(n-1)d)
= 22/2( 2×4+(22-1)5)
= 11(8+21×5)
= 11(8+105)
=11× 113
= 1243
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