find the sum of first 24 terms of the AP a1,a2,a3....an if it is known that a1+a5+a10+a15+a20+a24=225
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Answered by
7
Answer:
900
Step-by-step explanation:
LET FIRST TERM=a, COMMON DIFFERENCE=D
a1+a5+a10+a15+a20+a24=225
a+a+4d+a+9d+a+14d+a+19d+a+23d=225
6a+69d=225
2a+23d=75----------------(1)
Now sum of 24 terms
S24=24/2(2a+23d)
=12*(75)
=900
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