Question

find the sum of first 24 terms of the list of number whose nth term give by

Answer 1

The nth term is an=3+2n

So by using this we can find the value of terms like a1=5,a2=7,a3=9

and a24=51

Now the first term is 5 and the last term is 51 and the

difference is 2 by using the formula for sum of n terms i. e

sn =n/2(2a+(n-1)d)

so s24=24/2(10+23*2)

i. e 672 ans.

Hope This helps :)