Find the sum of first 24terms of the list of numbers whose nth term is given by an = 3+2n
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Answer:
Step-by-step explanation:
If n=1,
a1=3+(2×1)
a1=3+2
a1=5.
So, a=5.
a2=3+(2×2)
a2=3+4
a2=7
d=a2-a1
d=7-5
d=2.
We know that an=a+(n-1)d
So,a24=5+(24-1)2
a24=5+23×2
a24=5+46
a24=51.
Sn=n/2(a+an)
S24=24/2(5+51)
S24=12×56
S24=672.
Hope it helps you.
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