Find the sum of first 30 positive integers multiple of 6
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Answered by
80
Answer:
2790
Step-by-step explanation:
The numbers will be :
6,12,18,....t30
S= n/2[2a + (n-1)d]
= 15[12 + (29*6)]
= 15[6 + 6*30]
= 15*186
= 2790
Answered by
19
Step-by-step explanation:
this answer is totally right
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