find the sum of first 40 even numbers
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step 1. Address the formula, input parameters & values.
Input parameters & values:
The number series 2, 4, 6, 8, 10, 12, . . . . , 80.
The first term a = 2
The common difference d = 2
Total number of terms n = 40
step 2. apply the input parameter values in the AP formula
Sum = n/2 x (a + Tn)
= 40/2 x (2 + 80)
= (40 x 82)/ 2
= 3280/2
2 + 4 + 6 + 8 + 10 + 12 + . . . . + 80 = 1640
Therefore, 1640 is the sum of first 40 even numbers.......
Input parameters & values:
The number series 2, 4, 6, 8, 10, 12, . . . . , 80.
The first term a = 2
The common difference d = 2
Total number of terms n = 40
step 2. apply the input parameter values in the AP formula
Sum = n/2 x (a + Tn)
= 40/2 x (2 + 80)
= (40 x 82)/ 2
= 3280/2
2 + 4 + 6 + 8 + 10 + 12 + . . . . + 80 = 1640
Therefore, 1640 is the sum of first 40 even numbers.......
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