Question

find the sum of first 40 positive integers divisible by 6​

Answer 1

Answer:

PLease Mark me as Brainliest!

Explanation:

1-40 sum:

40*41/2=820

820/6=13.66666666666 with the 6 repeating forever

Answer 2

Answer:

HOPE IT HELPS YOU

Explanation:

$Sn= n/2[2a+[n-1]d]\\\\=40/2[2*6+[40-1]6]\\=20[12+39*6]\\=20[12+234]\\=20[246]\\=4920$