Question

Find the sum of first 40positive integer divisible by 6?

Answer 1

Answer:

a = 6

d=6

n=40

Sn=n/2(2a+39d)

=20(12+39(6))

=20(12+234)

=20(246)

= 4920

Answer 2

Answer:

Ello!

________Answer here __________

A.P =6,12,18..........

a=6,d=6

Sn=n/2 *2a(n-1)d

S40=40/2*12(40-1)6

S40=4920

hope helps ❤