Find the sum of first 40positive integer divisible by 6?
Answers
Answered by
1
Answer:
a = 6
d=6
n=40
Sn=n/2(2a+39d)
=20(12+39(6))
=20(12+234)
=20(246)
= 4920
Answered by
4
Answer:
Ello!
________Answer here __________
A.P =6,12,18..........
a=6,d=6
Sn=n/2 *2a(n-1)d
S40=40/2*12(40-1)6
S40=4920
hope helps ❤
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