find the sum of first 50 even natural number
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Answered by
19
a = 2
d = 2
n = 50
Sn = n/2 [ 2a +(n-1)d]
= 50/2 [ 4 + 49*2]
= 25 ( 4+98)
= 25 * 102
= 2550
d = 2
n = 50
Sn = n/2 [ 2a +(n-1)d]
= 50/2 [ 4 + 49*2]
= 25 ( 4+98)
= 25 * 102
= 2550
vsk96garg:
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Answered by
2
a = 2
d = 2
n = 50
Sn = n/2 [ 2a +(n-1)d]
= 50/2 [ 4 + 49*2]
= 25 ( 4+98)
= 25 * 102
= 2550
hope it helped ⚡
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