Find the sum of first 50 terms of the sequence 5, 5.5, 5.55,........
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Sn =n/2(2a +(n-1)d
Here n =50
a =5
d=5.5-5=0.5
Putting in formula
S50 =50/2(2×5+(50-1)0.5
=25(10+(49)×0.5)
=25(10+24.5)
=25(34.5)
=862.5
Here n =50
a =5
d=5.5-5=0.5
Putting in formula
S50 =50/2(2×5+(50-1)0.5
=25(10+(49)×0.5)
=25(10+24.5)
=25(34.5)
=862.5
sivakeerthu06pajznn:
wrong use GP formula
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