Question

find the value of k for which one root of the quadratic equation kxX-14x+8=0 is 2

Answer 1

Hey mate here is your answer

let

p(X)=kx²-14x+8=0

as 2 is a root of p(X)

it must satisfy the equation

i.e.p(2)=0

so

p(2)=k(2)²-14(2)+8=0

$4k - 28 + 8 = 0 \\ so \: 4k = 20 \\ k = 5 \\ hope \: it \: will \: help \: you \\ \\ mark \: me \: brainliest$
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