find the value of k for which one root of the quadratic equation kxX-14x+8=0 is 2
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Hey mate here is your answer
let
p(X)=kx²-14x+8=0
as 2 is a root of p(X)
it must satisfy the equation
i.e.p(2)=0
so
p(2)=k(2)²-14(2)+8=0
![4k - 28 + 8 = 0 \\ so \:<br /><br /> 4k = 20 \\ k = 5 \\<br /><br /> hope \: it \: will \: help \: you \\<br /><br /> \\ mark \: me \: brainliest 4k - 28 + 8 = 0 \\ so \:<br /><br /> 4k = 20 \\ k = 5 \\<br /><br /> hope \: it \: will \: help \: you \\<br /><br /> \\ mark \: me \: brainliest](https://tex.z-dn.net/?f=4k+-+28+%2B+8+%3D+0+%5C%5C+so+%5C%3A%3Cbr+%2F%3E%3Cbr+%2F%3E+4k+%3D+20+%5C%5C+k+%3D+5+%5C%5C%3Cbr+%2F%3E%3Cbr+%2F%3E+hope+%5C%3A+it+%5C%3A+will+%5C%3A+help+%5C%3A+you+%5C%5C%3Cbr+%2F%3E%3Cbr+%2F%3E+%5C%5C+mark+%5C%3A+me+%5C%3A+brainliest)
✌✌✌✌
let
p(X)=kx²-14x+8=0
as 2 is a root of p(X)
it must satisfy the equation
i.e.p(2)=0
so
p(2)=k(2)²-14(2)+8=0
✌✌✌✌
vampire002:
hey sujata do you know swarna
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