find the sum of first 8 multiple of 3
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First 8 multiples of 3=3,6,9,12,15,18,21,24
Now, sum of the 8 multiples of 3
3+6+9+12+15+18+21+24
=108
Now, sum of the 8 multiples of 3
3+6+9+12+15+18+21+24
=108
AakashMaurya:
Hey you should use arithmetic progression according to the question
Answered by
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Hey!!!
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Here is your answer!!!!
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Sum of first 8 multiple of 3
sn=n/2(2×a+(n-1)×d)
s8=8/2(2×3+(8-1)×3)
=4(6+7×3)
=4(6+21)
=4×27
=108
_________________
Here is your answer!!!!
________________
Here is your answer!!!!
_________________
Sum of first 8 multiple of 3
sn=n/2(2×a+(n-1)×d)
s8=8/2(2×3+(8-1)×3)
=4(6+7×3)
=4(6+21)
=4×27
=108
_________________
Here is your answer!!!!
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