Find the sum of first 8 multiple of 3
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A.P = 3,6,9,12......
a=3,d=3,n=8
Sn= n/2(2a+(n-1)×d
=> 8/2(2×3+(8-1)×3
=> 4 × (6+7×3)
=>4× 27
=> 108
so, the sum of first 8 multiple of 3 is 108
a=3,d=3,n=8
Sn= n/2(2a+(n-1)×d
=> 8/2(2×3+(8-1)×3
=> 4 × (6+7×3)
=>4× 27
=> 108
so, the sum of first 8 multiple of 3 is 108
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