Find the sum of first 8 multiples of 3.
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Step-by-step explanation:
First 8 multiples of 3 are:
- 3×1=3
- 3×2=6
- 3×3=9
- 3×4=12
- 3×5=15
- 3×6=18
- 3×7=21
- 3×8=24
Sum of the numbers =3+6+9+12+15+18+21+24=108
Answered by
0
Answer:
24 is answer
Step-by-step explanation:
in Ap 3,6,9,12,.....
a=3
D=3
n=8
then solve..
sn= n/2{2a+(n-1)d}
=4(6+21)
=108
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