find the sum of first 8 multiples of 3
TARUN2693:
n =8 a= 3 l = 24 , s8 = 8/2*(3+24) = 4*27=108
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3+6+9+12+15+18+21+24
=108 is sum of them
=108 is sum of them
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1
So the first 8 multiples of 3 form an AP
3 , 6 , 9 , .. 24
so we have
a = 3
l = 24
n = 8
Therefore Sn = n/2(a + l )
= 8/2(3 + 24)
=4(27)
108
hope this helps
3 , 6 , 9 , .. 24
so we have
a = 3
l = 24
n = 8
Therefore Sn = n/2(a + l )
= 8/2(3 + 24)
=4(27)
108
hope this helps
thanks Aman
wlcm
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