Question

Find the sum of first 8 multiples of 3 using AP

Answer 1

first multiple of 3=a=3

8th multiple of 3=l=24

common difference = 3

n=8

sum = (n/2)(a+l)

       =4(3+24)

        =108

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Answer 2

✨✔️Question : Find the sum of the first 8 multiples of 3.

•Formula used in this question :
$(s)n \: = \: \frac{n}{2} \: \times (a \: + \: {a}n)$


✔️✔️Answer:

First 8 Multiples of 3 = 3, 6, 9, 12, 15, 18, 21, 24.
a = 3
an = 24
n = 8

$(s)n \: = \: \frac{8}{2} \: \times \: ( 3 \: + \: 24)$

$(s)n \: = \: 4 \: \times \: 27$

$(s)n \: = \: 108$

Therefore, sum of the first 8 multiples of 3 is 108.

✨✔️HOPE IT HELPS YOU....
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