Find the sum of first 8 multiples of 3 using AP
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first multiple of 3=a=3
8th multiple of 3=l=24
common difference = 3
n=8
sum = (n/2)(a+l)
=4(3+24)
=108
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SwagSonu:
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✨✔️Question : Find the sum of the first 8 multiples of 3.
•Formula used in this question :
![(s)n \: = \: \frac{n}{2} \: \times (a \: + \: {a}n) (s)n \: = \: \frac{n}{2} \: \times (a \: + \: {a}n)](https://tex.z-dn.net/?f=%28s%29n+%5C%3A+%3D+%5C%3A+%5Cfrac%7Bn%7D%7B2%7D+%5C%3A+%5Ctimes+%28a+%5C%3A+%2B+%5C%3A+%7Ba%7Dn%29)
✔️✔️Answer:
First 8 Multiples of 3 = 3, 6, 9, 12, 15, 18, 21, 24.
a = 3
an = 24
n = 8
![(s)n \: = \: \frac{8}{2} \: \times \: ( 3 \: + \: 24) (s)n \: = \: \frac{8}{2} \: \times \: ( 3 \: + \: 24)](https://tex.z-dn.net/?f=%28s%29n+%5C%3A+%3D+%5C%3A+%5Cfrac%7B8%7D%7B2%7D+%5C%3A+%5Ctimes+%5C%3A+%28+3+%5C%3A+%2B+%5C%3A+24%29)
![(s)n \: = \: 4 \: \times \: 27 (s)n \: = \: 4 \: \times \: 27](https://tex.z-dn.net/?f=%28s%29n+%5C%3A+%3D+%5C%3A+4+%5C%3A+%5Ctimes+%5C%3A+27)
![(s)n \: = \: 108 (s)n \: = \: 108](https://tex.z-dn.net/?f=%28s%29n+%5C%3A+%3D+%5C%3A+108)
Therefore, sum of the first 8 multiples of 3 is 108.
✨✔️HOPE IT HELPS YOU....
✌✌
•Formula used in this question :
✔️✔️Answer:
First 8 Multiples of 3 = 3, 6, 9, 12, 15, 18, 21, 24.
a = 3
an = 24
n = 8
Therefore, sum of the first 8 multiples of 3 is 108.
✨✔️HOPE IT HELPS YOU....
✌✌
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