Question

find the sum of first 8multiple of 3​

Answer 1

here a=3

d=3

so sn=n/2{2a+(n-1)d}

=8/2(6+21)

4×27

=108

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Answer 2

Answer:

Step-by-step explanation:

AP- 3,6,9......

Sn= n/2[2a+(n-1)d]

S8=8/2[2×3+(8-1)3]

S8=4(6+7×3]

S8=4(6+21)=4(27)

S8=108

Sum of first 8 multiples of three is 108