Question

find the sum of first eight multiples of 3

Answer 1

The first 8 multiples of 3 are :  3, 6, 9, 12, 15, 18, 21, 24

Number of terms = 8

The first term = a1 = 3

The last term = a8 = 24

Find the sum:

Sn = n/2 ( a1 + an)

S8 = 8/2 (3 + 24)

S8 = 108

Answer: The sum of the first 8 multiples of 3 is 108.

Answer 2

Sum refers to the addition operation.

Multiples of a number is the number which is divisible by the number and by 1.

Hence, the first 8 multiples of three would be,

3*1=3

3*2=6

3=3=9

3*4=12

3*5=15

3*6=18

3*7=21

3*8=24

The multiples are 3,6,9,12,15,18,21,24.

Hence their sum,

3+6+9+12+15+18+21+24= 108

The answer is 108.

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