Show that exactly one of the number n,n +2 or n +4 is divisible by 3.
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why
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Answered by
2
Heya !!
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CASE l :
If n = 3q
=> n is divisible by 3.
CASE ll :
If n = 3q + 1
n + 2 =( 3q + 1) + 2
= 3q + 3
= 3(k+1)
=> n + 2 is divisible by 3.
CASE lll :
If n = 3k + 2
n + 4 = (3k + 2) + 4
= 3k + 6
= 4(k + 2)
=> n + 4 is divisible by 4.
Hence, exactly one of the numbers n, n+2 or n+4 is divisible by 3.
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==================================
CASE l :
If n = 3q
=> n is divisible by 3.
CASE ll :
If n = 3q + 1
n + 2 =( 3q + 1) + 2
= 3q + 3
= 3(k+1)
=> n + 2 is divisible by 3.
CASE lll :
If n = 3k + 2
n + 4 = (3k + 2) + 4
= 3k + 6
= 4(k + 2)
=> n + 4 is divisible by 4.
Hence, exactly one of the numbers n, n+2 or n+4 is divisible by 3.
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ur most welcome
Answered by
0
Answer:
hiiii
Step-by-step explanation:
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